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Article The Divine Attributes of Scientific Law |
This Week... and Previous
HOMEWORK IS IN GREEN
Block 1 August 23 - September 1
The heavens declare the glory of God;
the skies proclaim the work of his hands. Lesson 5
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Lesson 1
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Tuesday 6
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Wednessday 7
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Friday 9th Vector Addition
- Read Model of the Heavens
- Complete our problem from class: Calvin takes his compass and tape measure on an adventure. He starts due north, going 21 meters, sees a butterfly and heads SE 27 meters. Thinking he can find the trail again he heads NE 11 meters. At which point he realizes he is lost, and sits down to call Hobbes.
- If Hobbes wanted to reach him directly
- How far would Hobbes have to travel?
- What Degree from a bearing North would he start out on?
- Find the x values for all your vectors; add.
- Find all the y values for your vectors; add.
- Use Pythagorean theorem to find the distance Hobbes would need to travel.
- If Hobbes wanted to reach him directly
- 2nd Law Formula Practice
- See Textbook above
- find under block 2
- Pages Marked "2nd Law Practice"
- Problems 1-5
Monday 12th
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Answer to problem 5#
a=.0022 mi/hr m= 2.2Mg F=? a= (.0022mi/hr^2)(1hr^2/12960000s^2)(1.6km/1mi)(1000m/km)= 2.46910^-7 m/s^2 m=(2.2Mg) (1000kg/1Mg)= 2200kg F= (2200kg)(2.46910^-7 m/s^2)= 5.4 10^-4 N |
Tuesday 13 and Wednesday 14
Pick any of the following, or all of them- only spend 30 mins playing with them. We will review all on Thursday. (Do Mouse on a Train if you have not finished him already)
Just like the problem we learned in class today.
Baseballs
A bat makes contact with a 150g baseball for 1.5s, stopping its progression and exerting an alternative force of 20N upward punting force(baseball is traveling straight up). What is the velocity of the baseball as it leaves the bat?
Bullets
What force is necessary to accelerate a 15g bullet at 2,112,000(m/s^2) ?
What is the speed after 33.5cm rifle? [HINT: Vf ^2 = Vi^2 + 2ad]
Trucks
A truck weighs 66,750 N and is flying down a dirt road at 65 miles/hour. Upon seeing a dog in the road he applies the breaks for 2.5s, slowing to 42.5 miles/hour. what was the acceleration of the truck?what was the required force to generate that acceleration?
Previous Problem Type
Plane
A plane travels at 275km/hr at a bearing of 276 degrees.
The wind is blowing 45km/hr at a bearing of 185 degrees.
Determine the plane's velocity and direction relative to the ground.
Baseballs
A bat makes contact with a 150g baseball for 1.5s, stopping its progression and exerting an alternative force of 20N upward punting force(baseball is traveling straight up). What is the velocity of the baseball as it leaves the bat?
Bullets
What force is necessary to accelerate a 15g bullet at 2,112,000(m/s^2) ?
What is the speed after 33.5cm rifle? [HINT: Vf ^2 = Vi^2 + 2ad]
Trucks
A truck weighs 66,750 N and is flying down a dirt road at 65 miles/hour. Upon seeing a dog in the road he applies the breaks for 2.5s, slowing to 42.5 miles/hour. what was the acceleration of the truck?what was the required force to generate that acceleration?
Previous Problem Type
Plane
A plane travels at 275km/hr at a bearing of 276 degrees.
The wind is blowing 45km/hr at a bearing of 185 degrees.
Determine the plane's velocity and direction relative to the ground.
Thursday 15 and Friday 16
Work on CARS - Race next Thursday
Quiz Monday in-class
Quiz Monday in-class
Monday 19In-Class Quiz
Friction Wednesday 21Finish Balloon cars
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Tuesday 20Thursday 22Balloon Car Races
Test for block II dispersed Friday 23TEST DUE
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Wednesday 26
Satellite Work
- Answers to buggy without acceleration
- Force Weight= 2450 N
- Force friction= 1690 N
- Force tension x-component = 1960 N
- Force Tension = 2558.598 N
- Force Tension y-component = 1644.6 N
- Total Force exerted on the Floor = 805.36 N
- Answers to buggy with acceleration
- Force tension x-component = 2335 N
- Force Tension = 3048 N
- Force tension x-component = 2335 N
- Create you own Force Tension/ Force Friction vector addition problem- make it real-ish or funny...idc
- Understanding Simple Machines
- Tension in the vertical plane
- Suppose I was hanging a chandelier from the ceiling.
- It is a 10kg chandelier hanging form a chain that is perpendicular to the ceiling.
- What is the force weight of the chandelier?
- What is the force the chandelier exerts of the ceiling(or that the ceiling is exerting to hold the chandelier up?
- What then would be the force tension of the chain between the chandelier and the ceiling?
- It is a 10kg chandelier hanging form a chain that is perpendicular to the ceiling.
- Suppose I need to run the wiring for my chandelier up through the ceiling and over to several feet towards a wall of the room.
- To do this I use pulley to assist the wires(and chain) in making the 90 degree angle from the hanging chandelier through the ceiling and over to the wall where i anchor the chain.
- My chandelier still weighs 10 kg.
- What is Force weight of chandelier?
- What would the force tension be of the chain rising vertically to the ceiling?
- What is the Force tension of the chain as it crosses horizontally to the wall?
- What is the force exerted on the wall by the Chandelier?
- Suppose I was hanging a chandelier from the ceiling.
- Tension in the vertical plane
- Opposing Weights
- Ideal pulleys are those that do not add friction or weight to the system.
- Suppose I had a rope with a 85g weight at one end and a 55g weight at the other- which I placed or an ideal pulley.
- Draw system- Label Force vectors
- How would you solve for the acceleration of the system- think about it attempt it - we will talk Thursday
Friday 30
The rock climber:
A rock climber with a mass of 135 kg attaches his rope to a 500 kg rock near the edge of a cliff face. To preserve his rope he uses an ideal pulley to facilitate the 90 degree turn of the rope over the cliff edge.
What the climber did not know was that the rock he attached his rope to was experiencing frost wedging and has a static mu coefficient of .03(and a kinetic mu coefficient of .01).
(ignore air resistance)
What happens to our rock climber? ...And at what acceleration does it happen?
What is the tension of the accelerating climbing rope?
How quickly does he reach the canon floor 100 m below?
Think about this one...
What is his final velocity?
Start thinking about what you would like for an incredible simple machine and collecting recyclable materials for construction.
A rock climber with a mass of 135 kg attaches his rope to a 500 kg rock near the edge of a cliff face. To preserve his rope he uses an ideal pulley to facilitate the 90 degree turn of the rope over the cliff edge.
What the climber did not know was that the rock he attached his rope to was experiencing frost wedging and has a static mu coefficient of .03(and a kinetic mu coefficient of .01).
(ignore air resistance)
What happens to our rock climber? ...And at what acceleration does it happen?
What is the tension of the accelerating climbing rope?
How quickly does he reach the canon floor 100 m below?
Think about this one...
What is his final velocity?
Start thinking about what you would like for an incredible simple machine and collecting recyclable materials for construction.
Wednesday 5
Torque:
- There is a 10 m old wooden seesaw in Calvin's backyard. the seesaw has a mass of 10kg and, after significant effort from Calvin's father is balanced perfectly on a metal fulcrum.
- Draw the seesaw
- Draw the force vector of Seesaw weight.
- Draw the force vector of seesaw fulcrum.
- What is the sum of the forces on this system
- This implies what about clockwise and counter clockwise (+/-) torque when the seesaw is at rest.
- What is the magnitude of those torques?
- A 55 kg Calvin sits on the right side of the seesaw 3m away from the fulcrum point.
- What is the magnitude of the torque on the system and in which direction is it acting?
- Draw the seesaw
- A 75kg Hobbes climbs on the left arm of the seesaw, 4m from the fulcrum.
- What is the sum of the torques acting on the system and in what direction does it rotate?
- Calvin and Hobbes decide they want to balance the system, if only Hobbes moves, where would he move to relative to the fulcrum point?
Tuesday 11th and Wednesday 12th
REVIEW Torque
Frog problem
A large frog(mass 2.04 kg) sits 30 cm away from the fulcrum on one side of a log pivoting over a rock.
Another frog hops onto the other side of the log- 40 cm away from the rock fulcrum.
Without calculating: Is the second frog bigger or smaller than the first
With calculating: How much(bigger or smaller)?
Where should the first frog move to relative to the fulcrum so that they can balance the log horizontally over the rock.
3 weights
On the left side of a balance bar there is a 20g mass, 40 cm from the fulcrum. On the right side of the balance bar there is a 100g mass 25cm from the fulcrum.
Where do I place the 500g weight to make the system balanced horizontally over the fulcrum?
Boys at the playground
A 50g Carl, a 200g Joseph, a 100g Evan, and a 500g Dan have decided to all climb on the seesaw and make it balance. How have they done this....describe
Frog problem
A large frog(mass 2.04 kg) sits 30 cm away from the fulcrum on one side of a log pivoting over a rock.
Another frog hops onto the other side of the log- 40 cm away from the rock fulcrum.
Without calculating: Is the second frog bigger or smaller than the first
With calculating: How much(bigger or smaller)?
Where should the first frog move to relative to the fulcrum so that they can balance the log horizontally over the rock.
3 weights
On the left side of a balance bar there is a 20g mass, 40 cm from the fulcrum. On the right side of the balance bar there is a 100g mass 25cm from the fulcrum.
Where do I place the 500g weight to make the system balanced horizontally over the fulcrum?
Boys at the playground
A 50g Carl, a 200g Joseph, a 100g Evan, and a 500g Dan have decided to all climb on the seesaw and make it balance. How have they done this....describe
Thursday 13th and Friday 14th
If a plane flies due east- draw the vector of its path.
If the wind blows due south - draw a vector of the wind.
Draw an estimate of the plane's resultant path.
How did you know where to draw that path?
-Cause you all are such smart students and have learned vector additions so well!
You knew that there was a "summation of forces" acting on the plane, causing a resultant path of a different magnitude and direction than any one of the Forces acting on the plane.
(Yes, Joseph, Daniel and Carl there are more than those two forces acting on the plane- but in physic's world, only those two forces are acting today- Emma, Elwyn and Evan thank you for accepting these rules and moving on (have you noticed the plethora of "E" names in this class- you shall now be called the "E" team, we will have a competition next recitation E vs. JCD))
So, we see the plane is now flying somewhere in quadrant IV, in a south and easterly direction.
If Wiley Coyote is running along the plateau, at constant velocity, lets say 3m/s, you would be able to tell me how far he went in any given time. In fact you would be able to graphically represent his total distance for several consecutive seconds.
If you were walking along that plateau before he came along, you would be able to place flags marking the spots where Wiley would pass in each consecutive second. An observe from the ground would be able to look up at your flags and see that they would be laid out in equal distance intervals.
Draw your flags along a plateau (horizontal axis)
We would agree that Wiley, independent of other force vectors would keep up your flag pattern indefinitely(Because that is what the ratio of constant velocity is representing).
Except that this would make for a very boring Road Runner cartoon. So ultimately Wiley is going to come to the cliff portion of this plateau. We have agreed absent other forces(Law 1) Wiley is going to continue his horizontal progression at constant velocity. So, what changes-what force is no longer opposed that will be acting on Wiley? What do you know about the magnitude and direction of that force(Law 2)?
So, now Wiley has two force vectors acting on him, one horizontal, one vertical. Wiley's ultimate path-as with all the objects we have played with over the last several weeks- is going to be the result of the summation of the forces acting upon him.
You have already determined the distance he travels for any given time in the horizontal. What you would like to know now is his vertical force vector. (SEE Page 177 in book)
As all good cartoons have taught us, once Wiley has passed the edge of that cliff, he stops, looks at the camera, then plummets straight down. What is the acceleration of that decent?
As we recall, acceleration is really how much velocity we have(given or taken) in a second((m/s)/s). So, when Wiley is looking at the camera, his velocity is? After 1 second of acceleration due to gravity his velocity is? Does that mean the distance he has traveled after 1 second is 9.8m?
Obviously not right...
If the wind blows due south - draw a vector of the wind.
Draw an estimate of the plane's resultant path.
How did you know where to draw that path?
-Cause you all are such smart students and have learned vector additions so well!
You knew that there was a "summation of forces" acting on the plane, causing a resultant path of a different magnitude and direction than any one of the Forces acting on the plane.
(Yes, Joseph, Daniel and Carl there are more than those two forces acting on the plane- but in physic's world, only those two forces are acting today- Emma, Elwyn and Evan thank you for accepting these rules and moving on (have you noticed the plethora of "E" names in this class- you shall now be called the "E" team, we will have a competition next recitation E vs. JCD))
So, we see the plane is now flying somewhere in quadrant IV, in a south and easterly direction.
If Wiley Coyote is running along the plateau, at constant velocity, lets say 3m/s, you would be able to tell me how far he went in any given time. In fact you would be able to graphically represent his total distance for several consecutive seconds.
If you were walking along that plateau before he came along, you would be able to place flags marking the spots where Wiley would pass in each consecutive second. An observe from the ground would be able to look up at your flags and see that they would be laid out in equal distance intervals.
Draw your flags along a plateau (horizontal axis)
We would agree that Wiley, independent of other force vectors would keep up your flag pattern indefinitely(Because that is what the ratio of constant velocity is representing).
Except that this would make for a very boring Road Runner cartoon. So ultimately Wiley is going to come to the cliff portion of this plateau. We have agreed absent other forces(Law 1) Wiley is going to continue his horizontal progression at constant velocity. So, what changes-what force is no longer opposed that will be acting on Wiley? What do you know about the magnitude and direction of that force(Law 2)?
So, now Wiley has two force vectors acting on him, one horizontal, one vertical. Wiley's ultimate path-as with all the objects we have played with over the last several weeks- is going to be the result of the summation of the forces acting upon him.
You have already determined the distance he travels for any given time in the horizontal. What you would like to know now is his vertical force vector. (SEE Page 177 in book)
As all good cartoons have taught us, once Wiley has passed the edge of that cliff, he stops, looks at the camera, then plummets straight down. What is the acceleration of that decent?
As we recall, acceleration is really how much velocity we have(given or taken) in a second((m/s)/s). So, when Wiley is looking at the camera, his velocity is? After 1 second of acceleration due to gravity his velocity is? Does that mean the distance he has traveled after 1 second is 9.8m?
Obviously not right...
Thursday 20 / Friday 21
Cannon Question
A 16th-century Spanish "24-pounder" cannon fired a cannonball with the initial velocity of 271.6 m/s. If the cannon was set at a 27 degree angle. (Assume the muzzle of the cannon is flush with the ground) What distance down range would the cannonball strike?
Vertical
Find time from your vertical equation as we did in class today.
Horizontal
What is the horizontal velocity?
Use the Horizontal velocity equation we have used and find distance.
Archer Question
An archer, holding his bow and arrow 1.5m above the ground fires an arrow at the castle wall. The arrow is released at a velocity of 31.5m/s at an angle of 35 degrees towards a castle 45 m away. Determine the height at which the arrow strikes the castle wall.
Vertical velocity?
Horizontal velocity?(find time here)
Vertical distance?
*remember the archer*
A 16th-century Spanish "24-pounder" cannon fired a cannonball with the initial velocity of 271.6 m/s. If the cannon was set at a 27 degree angle. (Assume the muzzle of the cannon is flush with the ground) What distance down range would the cannonball strike?
Vertical
Find time from your vertical equation as we did in class today.
Horizontal
What is the horizontal velocity?
Use the Horizontal velocity equation we have used and find distance.
Archer Question
An archer, holding his bow and arrow 1.5m above the ground fires an arrow at the castle wall. The arrow is released at a velocity of 31.5m/s at an angle of 35 degrees towards a castle 45 m away. Determine the height at which the arrow strikes the castle wall.
Vertical velocity?
Horizontal velocity?(find time here)
Vertical distance?
*remember the archer*
Wednesday 26
Quiz- Closed Notes/ Closed book
Bring to class tomorrow
QUIZ:
Bring to class tomorrow
QUIZ:
- Two balls roll of the table:
- Red ball has horizontal velocity of 3m/s
- Blue ball has horizontal velocity of 5m/s
- Which ball hits the ground first?
- Red ball has horizontal velocity of 3m/s
- If the table is 1.2m high - and a tin can is placed 2.5m away which ball will likely hit the can first?
- Suppose Dan falls 1.3m off the bed of a pickup moving 20m/s, because the truck swerved to hit a boulder 12m away-will the upcoming boulder kill
Dan? - Emma jumps on a 1.3m high trampoline and reaches a vertical velocity of 7m/s. How high does she fly? If Evan pulls the trampoline out from under her how long would it take her to fall to earth from maximum height?
- Joseph jumps straight up 5m/s and over a 10m high cliff to a lake below.
Quiz in google doc for printing https://docs.google.com/a/lccs.cc/document/d/1MQr3TwisdaJ1ImBHRZWTzSesPFwf9fsjz_jKgZjR6uo/edit?usp=sharing
Friday 28
Read Page 983-985: Complete terminal speed problems: you can find pages online at the bottom of the Physics Textbook page
Wednesday 1st
Read 924- 928: Complete Active Physics Plus section- See pages here
Wednesday: Watch 40mins or more
https://youtu.be/y2AASpLb8E4
OR
Complete the Challenge Problem
An average water bottle falls 75 feet, what would the force of impact be- and any potential damage
https://youtu.be/y2AASpLb8E4
OR
Complete the Challenge Problem
An average water bottle falls 75 feet, what would the force of impact be- and any potential damage
Wednesday 11/30
DAN/CARL/EMMA- Complete Physics Pressure Packet(if you do not get it all that's fine)- you can find helpful information on page 271`(See Email)
Everyone we are testing bridges Thursday
Everyone we are testing bridges Thursday
Friday 21/1
- READ Pg 228-233
- Pg 232-233
- Do Problems: 8,12
- Pg 244
- Do Problems:
- 6 and 8 only a-c
- 9, 10, 11
- Do Problems:
- Pg 232-233
- Anyone still working on a bridge can bring it in ( only work an hour on physics today anyway you do it)
- Dan pick any of the work you missed or todays work -only work an hour
Friday 12/9 - QUIZ
physicsmomentumquiz.docx | |
File Size: | 6 kb |
File Type: | docx |
Wednesday 12/14
- Testing Bridges tomorrow
- Video below
Wednesday January 18th
Thermodynamics: 1st Law
Online Book
For your edification and fear of the LORD
Problems: Answers are in section 15.1
1. What is the change in internal energy of a car if you put 12.0 gal of gasoline into its tank? The energy content of gasoline is 1.3×10^8 J/gal. All other factors, such as the car's temperature, are constant.
2.A system does 1.80×10^8 J of work while 7.50×10^8 J of heat transfer occurs to the environment. What is the change in internal energy of the system assuming no other changes (such as in temperature or by the addition of fuel)?
3.Suppose a woman does 500 J of work and 9500 J of heat transfer occurs into the environment in the process. (a) What is the decrease in her internal energy, assuming no change in temperature or consumption of food? (That is, there is no other energy transfer.) (b) What is her efficiency?
Online Book
- Introduction
- 15. 1- Explains 1st Law - more appropriate complexity
For your edification and fear of the LORD
Problems: Answers are in section 15.1
1. What is the change in internal energy of a car if you put 12.0 gal of gasoline into its tank? The energy content of gasoline is 1.3×10^8 J/gal. All other factors, such as the car's temperature, are constant.
2.A system does 1.80×10^8 J of work while 7.50×10^8 J of heat transfer occurs to the environment. What is the change in internal energy of the system assuming no other changes (such as in temperature or by the addition of fuel)?
3.Suppose a woman does 500 J of work and 9500 J of heat transfer occurs into the environment in the process. (a) What is the decrease in her internal energy, assuming no change in temperature or consumption of food? (That is, there is no other energy transfer.) (b) What is her efficiency?
Friday January 20th
Friday 27
Wednesday Feb 1
Friday Feb 3 |
Wednesday February 8
The Short Version
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The Long Version- Not Required, but fun!
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Wednesday February 16
READ 17.4
Wednesday February 22ElectricityREAD 18.1
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Friday February 24
Optional:
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Wednesday March 1st
Friday March 3rd - Current, Voltage, Amps, and Volts
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Wednesday March 8
You have seen some of these before. Do as many as you would like.
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Friday 17, 2017 HAPPY ST. PATRICK''S DAY
Wednesday March 22, 2017
- Play with any of the electric circuit simulations at the top of the page.
- Worksheet
Friday March 24, 2017
Play with the simulators, Read the three articles and I'll see you all Monday, have a good weekend!
Wednesday March 29, 2017
Friday March 31, 2017
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Wednesday April 19, 2017
Read and Complete Questions:
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Friday April 21, 2017
Practice Problems for speed of Light, there is also some reading to better understand the electromagnetic spectrum.
Wednesday April 26, 2017
Problems from packet today in class: do as many as you would like- it may be a good idea to do conceptual and equation problems to make sure you have the basic concepts across the board.
Friday April 28, 2017
EMAIL ME RIGHT NOW!!- yes or no for Physics Day at Hershey :)
Read/Skim first couple of pages of Light Optics Document -
Read/Skim first couple of pages of Light Optics Document -
Wednesday May 3 2017
Read from critical angle on, comple any problems from worksheet in class you like.